You have done so, and I am grateful!! and also sorry! π
(h/t to a mutual who shared this link). ping me? alex@stainless.com
@rattrayalex.bsky.social
Founder, Stainless alexrattray.com
You have done so, and I am grateful!! and also sorry! π
(h/t to a mutual who shared this link). ping me? alex@stainless.com
Hi Tom, would love to help here! Ping me? alex@stainless.com
05.03.2025 00:34 β π 0 π 0 π¬ 1 π 0