Someone take him back to pmd he's been everywhere but there
#pmd #pmdoc #zorua #fennekin #spritzee #lor
@amethystt.bsky.social
They/she I draw animals on my computer, and play lots of games
Someone take him back to pmd he's been everywhere but there
#pmd #pmdoc #zorua #fennekin #spritzee #lor
torturing Aspen. His backstory is that he is on parole, so I suppose he would be iron lunged
#pokemon #zorua #pmd #pmdoc
the raising cane's zoroark from the discord gif search
#furry #pokefur #zoroark #furryart
Pmd oc team that I wanna make a comic about at some point
I gave Rivers (spritzee, former human) two partners bc I love her and want them to have friends but made them both foxes bc I hate her and want them to feel isolated
#pokemon #pmd #pmdocs #spritzee #zorua #fennekin
September is already over?
30.09.2025 15:11 β π 0 π 0 π¬ 0 π 0I should draw more. <- is way too busy with college to draw more
21.09.2025 22:15 β π 1 π 0 π¬ 0 π 0aaa I have this social media... I guess I'll go here too
art commissions! Look at tha image for info
only payment method I have set up right now is venmo but I'm willing to set others up
#furry #furryart #art #artcomms #furryartcomms #artcommissions
here, have an #airplanedragon version of me
20.03.2025 21:09 β π 0 π 0 π¬ 0 π 0ZORUA THURSDAY #pokemon #zorua #pokemonfanart
14.03.2025 01:36 β π 9 π 1 π¬ 1 π 0aawa need to actually use this
09.03.2025 19:50 β π 0 π 0 π¬ 0 π 0The Amethyst has been inactive here! Have some art I made recently
#furry #furryart
We might be back to art, might also rebrand
made something for the same friend, tried out new shading techniques
#furry #furryart
gonna do lots of experimenting with brushes with my next few things
watercolor brushes in krita are kinda prebby
#art #furryart
experimenting with new brushes, I like where my talents are going
16.10.2023 01:16 β π 0 π 0 π¬ 0 π 0more old art
08.10.2023 03:42 β π 1 π 0 π¬ 0 π 0more artwork for a friend I made in the past
06.10.2023 01:21 β π 0 π 0 π¬ 0 π 0some art from a bit ago I made for a friend
04.10.2023 19:42 β π 4 π 0 π¬ 0 π 0