Episodes will be released at 11am each and every Sunday, so get that in your download diaries π¨
Feel free to follow us here, and on βXβ, for regular updates on competitions with @Newbery_Cricket, future episodes, and guest announcements.
Have a great week π
26.10.2025 19:09 β π 0 π 0 π¬ 0 π 1
Great to have Mark Church back with a new podcast and sidekick. Here's episode one of Church and Vickers. You just know it'll be terrific:
open.spotify.com/episode/7rJx...
26.10.2025 11:24 β π 5 π 3 π¬ 3 π 0
Episode 1 - Introduction with Mark Church and Hector Vickers
Thank you to everyone who listened to todayβs episode - itβs great to be underway!
If you liked what you heard, please rate and review us wherever you get your podcasts, and send in Sermon suggestions for Mark Church, to:
sundayservice.pod@yahoo.com
open.spotify.com/episode/7rJx...
26.10.2025 19:07 β π 2 π 0 π¬ 0 π 0
π¨Itβs new episode day!π¨
Stop whatever you are doing at 11 am, and listen to the first episode of βSunday Service with Church and Vickersβ which will be out on all platforms.
Hereβs what to expect from the opening episode π
26.10.2025 08:15 β π 4 π 1 π¬ 0 π 1
Sponsorship announcement!
Sunday Service are excited to be working alongside @Newbery_Cricket on this new project.
Tune in for the first episode, tomorrow at 11 am, to hear what prizes they have in store for our competition winners π
newbery.co.uk
25.10.2025 18:59 β π 2 π 0 π¬ 0 π 0
@backandacross gives you his β3 reasons whyβ you should tune in to the first episode of βSunday Service with Church and Vickersβ
Make sure to give us a follow to find out more every week about what to expect from forthcoming episodes π
11 am, this Sunday - donβt miss it
25.10.2025 09:04 β π 1 π 0 π¬ 0 π 0
Hello and welcome to the official Bluesky account of the βSunday Service with Church and Vickersβ, cricket podcast.
The first episode airs this Sunday, at 11am, where the BBCβs Mark Church, and cricket journalist, Hector Vickers, take you through what to expect from the new series.
See you there!
24.10.2025 16:04 β π 3 π 0 π¬ 0 π 0