@doyachili.bsky.social
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12.09.2025 14:22 β π 702 π 207 π¬ 15 π 4
after many months, I have finally beat solo expert from Wii party.
ITβS OVER
30.08.2025 23:41 β π 0 π 0 π¬ 0 π 0cute!
17.08.2025 13:06 β π 1 π 0 π¬ 0 π 0
26.07.2025 21:29 β π 0 π 0 π¬ 0 π 0
Happy Pride Month from Missadaxio!
You are loved. You are valid.
everything is ToGLA
31.05.2025 16:59 β π 0 π 0 π¬ 0 π 0Finally done with 10th grade, expect more activity
30.05.2025 18:15 β π 1 π 0 π¬ 0 π 0doyachili
30.05.2025 00:50 β π 0 π 0 π¬ 0 π 0Can I make round -1
13.05.2025 20:09 β π 0 π 0 π¬ 1 π 0letβs go
13.05.2025 00:24 β π 0 π 0 π¬ 0 π 0cuteness overload
05.04.2025 02:10 β π 1 π 0 π¬ 0 π 017!!!!!!!!
13.03.2025 11:08 β π 0 π 0 π¬ 0 π 0
#GVerse π³οΈβπππΊπΈ
10.03.2025 22:50 β π 4887 π 3723 π¬ 202 π 248
09.03.2025 16:26 β π 23 π 3 π¬ 2 π 0
redsky
26.02.2025 13:39 β π 1 π 0 π¬ 0 π 0AVGN episode 147
18.02.2025 21:37 β π 0 π 0 π¬ 0 π 0happy birthday zed guy :D
18.02.2025 12:27 β π 1 π 0 π¬ 0 π 0as somebody who had to private their twitter bc of this, I do not blame you.
16.02.2025 00:46 β π 0 π 0 π¬ 0 π 0mfw im tryna get information but then [THIS VIDEO IS SPONSORED BY ITEM HERE]
11.02.2025 13:20 β π 0 π 0 π¬ 0 π 0β€οΈ
06.02.2025 13:32 β π 1 π 0 π¬ 0 π 0Im pretty much leaving there too.
06.02.2025 02:55 β π 0 π 0 π¬ 1 π 0yes
01.02.2025 14:21 β π 0 π 0 π¬ 0 π 02024 has been a very bad year for me, hopefully 2025 will be better
31.12.2024 22:12 β π 0 π 0 π¬ 0 π 0will missadaxio ever get bluesky
30.11.2024 20:32 β π 0 π 0 π¬ 1 π 0Itβs kind of us with decision when you use Twitter or Bluesky. Bluesky is way more active, but Twitter has more companies of interests.
28.11.2024 22:12 β π 0 π 0 π¬ 0 π 0
I usually play with a black remote, but it got lost
pink power finally wins!
28.11.2024 16:12 β π 0 π 0 π¬ 0 π 0*weclome yo bsky
16.11.2024 03:40 β π 1 π 0 π¬ 0 π 0Weclome yo blue sky!
16.11.2024 03:39 β π 1 π 0 π¬ 1 π 0Have you tried hammering it to align it?
11.11.2024 21:26 β π 1 π 0 π¬ 0 π 0btw itβs like 11 here I gotta get some rest
11.11.2024 04:01 β π 1 π 0 π¬ 0 π 0
