Wait till they see you derive a formula for max. distance using SUVAT and Integration methods. Now thatβs a beauty!
14.09.2025 12:46 β π 0 π 0 π¬ 1 π 0@mqkhan.bsky.social
Wait till they see you derive a formula for max. distance using SUVAT and Integration methods. Now thatβs a beauty!
14.09.2025 12:46 β π 0 π 0 π¬ 1 π 0Ah!! Excellent. Thank you!
Any chance you may do videos for the 3 optional applications for further maths (mechanics, statistics, discrete), AQA spec?? (Pretty pleaasssee)
I find your method of teaching very beneficial.
If not, what do you recommend for those sections? Thanks!
Why would I need to subtract from 90. Iβm a bit confused. Wouldnβt my answer be sufficient as a bearing. Vector is of length rt.1042 of bearing 16.2Β° (I.e. relative to the x axis. What am I missing here?
01.09.2025 20:21 β π 0 π 0 π¬ 1 π 0Sorry. J5-02.
01.09.2025 20:10 β π 0 π 0 π¬ 1 π 0Hi Jack. Got a question on your a level maths vids. For Vid J2-02 Vector Problem 2, you drew the angle above the vector. When I attempted it I drew it from the x axis to the vector so my answer was 16.2Β°, and yours was 73.8Β°. I was wandering why you drew the angle where you did..?
01.09.2025 19:34 β π 0 π 0 π¬ 1 π 0