#MetaphorRefantazioSweepstakes ππΎ
29.05.2025 23:58 β π 0 π 0 π¬ 0 π 0@korphon.bsky.social
he/him, 17 k0rphon or korph on most socials
#MetaphorRefantazioSweepstakes ππΎ
29.05.2025 23:58 β π 0 π 0 π¬ 0 π 0Custom Xbox controller displayed in a decorative stand themed around the game "Metaphor: ReFantazio." The controller features artwork of two anime-style characters and sits in front of a stylized background with a crowned silhouette of a character's head. The stand includes the game's title in bold, black text on a golden base.
Fight for the throne in Metaphor: ReFantazio with a custom Xbox Wireless controller!
Follow & Repost with #MetaphorRefantazioSweepstakes for a chance to win. There will be 5 lucky winners.
Ages 18+. Ends May 29, 2025. See full rules: xbx.lv/3YX3jfM
broken bone tokennn
putting the bones in the token model rn and it doesn really look as cool as it sounds so have this doodle of token with a broken leg #femtanyl
14.11.2024 19:43 β π 54 π 10 π¬ 1 π 0He was in the generation RIGHT before the switch so hes kinda recent(im coping with being old)
18.10.2024 13:36 β π 1 π 0 π¬ 1 π 0Yeah he dropped via mystery gift i think
18.10.2024 13:35 β π 1 π 0 π¬ 0 π 0Something something check point something something obligation pokemon
I love gen 7 your honor
I fear ill change my layout on here a million times til i find one i rly fw
17.10.2024 21:43 β π 0 π 0 π¬ 0 π 0You a damn lie
17.10.2024 21:42 β π 1 π 0 π¬ 1 π 0A.B.A for the Guilty Gear likers
#guiltygear #GGST #fightinggame #fgc #art
Lob 30 bucks
17.10.2024 21:39 β π 0 π 0 π¬ 1 π 0Theyre all brazilian
07.10.2024 01:24 β π 1 π 0 π¬ 1 π 0chat are there monkie kid fans on here
07.10.2024 01:23 β π 1 π 0 π¬ 1 π 0A virtual certificate with text "Celebrating 10M users on Bluesky, #1,535,813, korph-ish βͺ@korphon.bsky.socialβ¬, joined on Oct 15, 2023"
Bluesky now has over 10 million users, and I was #1,535,813?!?
07.10.2024 01:23 β π 2 π 0 π¬ 0 π 0Jaky ass tweet
07.11.2023 22:39 β π 1 π 0 π¬ 1 π 0if twitter doesnt work out yk the drill
15.10.2023 22:31 β π 3 π 0 π¬ 0 π 0