SEC officials will work tonight's @CFBPlayoff title game b/w Ohio State & Notre Dame. It's same crew that worked Fiesta Bowl b/w Penn State & Boise State #CFBPlayoff
20.01.2025 17:23 β π 15 π 2 π¬ 2 π 5@everythingtxst.bsky.social
Fan Account All sports things #TXST. ππβ½οΈπβΎοΈπ₯β³οΈππ #PHXSuns #UF π#PuraVidaπ¨π·β½οΈ #GirlDad
SEC officials will work tonight's @CFBPlayoff title game b/w Ohio State & Notre Dame. It's same crew that worked Fiesta Bowl b/w Penn State & Boise State #CFBPlayoff
20.01.2025 17:23 β π 15 π 2 π¬ 2 π 5There are 82 bowl eligible teams (includes UVa-VT winner) for 82 spots with only 1 game remaining
If New Mexico wins at Hawaii, there will be 83 teams for 82 spots. Who gets left out determined by conference tie ins. It is not automatic that independent UConn would be eliminated if UNM wins
GJ Kinne bursting or shattering the highest Sun Belt coaching mark! #TXST
22.11.2024 01:05 β π 3 π 0 π¬ 0 π 0#TXST HC GJ Kinneβs seven-year extension that averages $2million per year would make him the highest-paid coach in the Sun Belt Conference.
21.11.2024 23:51 β π 6 π 3 π¬ 1 π 0Homecoming game! #EatEmUpCats #SWT #txstatefootball
17.11.2024 11:49 β π 4 π 1 π¬ 0 π 0Ryan Clark on ESPN with his arms out in a white shirt with a black tie and a jacket that is half blue and half blue and white plaid
My man RC looks like he should be flipping a coin to determine Batman's fate
19.11.2024 00:54 β π 3234 π 416 π¬ 82 π 57βAnytime you can get bowl eligible for the second year in a row, itβs pretty special so you want to celebrate it. What better way than to jump in the river with these guys?β
Dominance on homecoming has #TXST bowl eligible again. www.expressnews.com/sports/artic...
Having flashbacks of greatness after seeing #BarrickNealy on the sidelines in #SWT garb. #TXST #Sanmarcos #Texas #Bobcat #football
17.11.2024 16:42 β π 4 π 1 π¬ 0 π 0#TXST Bowl Eligibility Unlocked Achievement River Jump
17.11.2024 06:54 β π 7 π 0 π¬ 0 π 1LMAO - Love itπ€£
15.11.2024 21:56 β π 3 π 0 π¬ 0 π 0π₯
15.11.2024 16:29 β π 3 π 0 π¬ 1 π 0