"< 20°"
Imagine 🔺️ABD has been sheared, A || to BD, from where <ACB=<ACD=90° and 🔺️s ACB & ACD are congruent, so 🔺️ACD has been sheared 2× as far as 🔺️ACB, so <CAD is less than <BAC (which is 10°). So <BAD must be less than 20°.

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45 cm?

04.04.2025 12:08 — 👍 0    🔁 0    💬 0    📌 0

Satisfraction. Task 16A

04.04.2025 09:02 — 👍 4    🔁 2    💬 0    📌 0