Thanks!
25.08.2025 22:38 β π 0 π 0 π¬ 0 π 0@normalsubgroup.bsky.social
Mathematician, mathematics educator and mathematics enthusiast. He/him.
Thanks!
25.08.2025 22:38 β π 0 π 0 π¬ 0 π 0Perfect for one of the things. Thanks
25.08.2025 22:33 β π 1 π 0 π¬ 0 π 0I might have a $150 budget to buy games for a math student lounge. (Like chess board various puzzles). Undergrad students. Maybe 15 use it, mix of 1st-4th year students.
For those who have recent experience with this:
What works really well for this type of thing?
Is that your first time for Poutine??
05.07.2025 13:40 β π 0 π 0 π¬ 1 π 0Yeah itβs possible I did one at school or such as a kid but just donβt remember. Think you may have been up CN tower one more time than you think. 1979, summer, was when I went up.
05.07.2025 13:39 β π 0 π 0 π¬ 0 π 0I guessed the stampede correctly (I also had a chance to go but did not go) but thought you had been to a territory. Guessed Inukshuk was your other one.
05.07.2025 13:30 β π 0 π 0 π¬ 2 π 0Iβm guessing the two that youβre missing are both in the 2nd column, one near the top and one near the bottom
05.07.2025 13:26 β π 0 π 0 π¬ 1 π 0Maybe a couple more. In Banff, I avoid horned (and horny) very large beasts at close range. Probably all elk. Itβs possible I did one of the others without realizing or remembering, Iβm so oldβ¦
05.07.2025 11:24 β π 0 π 0 π¬ 1 π 0Cool. Iβm only 17.
05.07.2025 11:19 β π 0 π 0 π¬ 0 π 0Or the authors tried to get it published, perhaps multiple times, and by way of bad luck (ignorant referees), the paper was always rejected.
Or there are multiple authors who no longer like each other and one is sabotaging the rest by refusing to allow it to be submitted.
A mathematician who transforms an extremely hard problem into several other problems that are also extremely hard, but each one slightly easier possibly, has had a great day.
#Mathematics
Thank you!!
05.04.2025 14:24 β π 0 π 0 π¬ 0 π 0Pleased with this result, although technical :) kwnsfk27.r.eu-west-1.awstrack.me/L0/https:%2F...
05.04.2025 11:03 β π 3 π 0 π¬ 1 π 0Bought a bunch of high quality PPC and PPE (protection) in case these items are about to become more difficult to obtain (or at least much more expensive) in the near futureβ¦.
26.01.2025 18:39 β π 2 π 0 π¬ 0 π 0If they attempt to enter your home or your workplace, ask for a warrant. Sometimes they will try to use other, non qualifying paperwork. They need a warrant.
You have the right to remain silent. Assert it. You have the right to a lawyer. Ask for one.
black and white photo of myself with long hair, part of it covering my left eye and with gentle friendly smile
a split view of a document on a left side page from what appear to be lecture notes from mathematics and on the right side loosely positioned integrals, illustrating steps of proving the convergence of vartheta-integral
Hello maths/physics community at bluesky ππ»
My name is Viktor, and having been frustrated by the countless hours I spent studying and deciphering math from long, linear, exhausting paragraphs of text, I am now pioneering spatial writing to make studying and reading much friendlier for our brains.
Glad youβre feeling better!
08.01.2025 00:10 β π 1 π 0 π¬ 1 π 0βHappy New Yearβ is an annual exercise in modular arithmetic.
Further proof that everybody LOVES Mathematics.
A page announcing the Mathematical Art Digital Exhibition at Queens College, which was developed to inspire, inform, and engage students mathematically at Queens College and worldwide.
I am excited to announce the opening of the Mathematical Art Digital Exhibition at Queens College. The exhibition features the work of 27 mathematical artists representing 10+ countries. View the exhibition at math.qc.cuny.edu/made-gallery and see the artwork, artist bios, and links to learn more.
03.12.2024 13:59 β π 49 π 17 π¬ 4 π 12Verify that both sides are 36x^3+66x^2+42x+9. Using x=166 as example.
Solution (2 of 2). The other key point is, with d the number of digits in x (choosing x from 1, 16, 166, 1666, etc) the right sides are:
(x)10^{2d}+(1/2)10^{2d}+(2x+1). But 6x+4=10^d. So the right sides are
(x+0.5)(6x+4)^2+(2x+1).
X^3+(2x+3)^3+(3x+2)^3 with x=166 as an example. With d the number of digits in our preferred choices of x, 10^d=6x+4 and 10^{2d}=36x^2+48x+16.
Solution. (Part 1 of 2). A key point is that the left sides of the equations have the form:
X^3+(2x+3)^3+(3x+2)^3. Also, for the x we are using (x=1, 16, 166, etc), 6x+4 is a power of 10, and therefore, so is (6x+4)^2.
Numerical pattern: 1^3+5^3+3^3=153. 16^3+50^3+33^3=165033. 166^3+500^3+333^3=166,500,333. And so on.
Testing alt text to make sure I can do it. I saw this on another social media site. If it looks like alt text works for me, Iβll post the answer in 2 replies. A picture in each reply. The other site does not have an alt text option that I know about.
01.12.2024 12:22 β π 3 π 1 π¬ 1 π 0I agree with this except Iβve tended to use βpropositionβ* for technical things that may not be of interest elsewhere. But yes, lemma is ideally a reusable neat tool. And vibes. Mostly vibes.
*I almost never use proposition.
Reviewer 1.5?
17.11.2024 01:27 β π 1 π 0 π¬ 0 π 0I remember in the late 1980s, my prof coming to Putnam practice and laughing about how every calc book uses trapezoids, and a Monthly article had just pointed out how rectangles using midpoints are more accurate.
16.11.2024 15:16 β π 1 π 0 π¬ 0 π 0I must have the wrong ap. I press β@β at the top and nothing happens. Will probably settle here anyway so itβs not worth working on it.
16.11.2024 15:09 β π 1 π 0 π¬ 1 π 0Iβve been there for a while but donβt seem to use it.
16.11.2024 14:57 β π 0 π 0 π¬ 1 π 0I have trouble understanding how threads works. At least the ap I have.
By contrast, Bluesky is so clear. I just press one button at the top and I only look at people I follow. My post here is mostly a joke.
Bluesky told me that its algorithm would decide what I like based on the first 10 things I βlikeβ so now Iβm afraid to click that like button for any reason. Too much pressure.
16.11.2024 14:29 β π 3 π 0 π¬ 2 π 0Vermont
15.11.2024 12:36 β π 3 π 0 π¬ 0 π 0