Adds at least two inches
31.10.2025 20:37 β π 1 π 0 π¬ 0 π 0@mpalmer.bsky.social
Adds at least two inches
31.10.2025 20:37 β π 1 π 0 π¬ 0 π 0Imagine being mad at this because Ted or something lol
31.10.2025 20:37 β π 2 π 0 π¬ 0 π 0Lol just the tip
31.10.2025 16:44 β π 0 π 0 π¬ 0 π 0π
31.10.2025 15:23 β π 2 π 0 π¬ 0 π 0πππ
31.10.2025 15:22 β π 0 π 0 π¬ 1 π 0Itβs going to be an absolute vibe.
31.10.2025 15:12 β π 1 π 0 π¬ 1 π 0Tedβs π looks even bigger in person.
31.10.2025 14:41 β π 5 π 0 π¬ 3 π 0Schneider back to his normal managerial shenanigans.
18.10.2025 01:02 β π 0 π 0 π¬ 0 π 0And Grant Devine hitting one out in the HR derby π
17.10.2025 21:26 β π 0 π 0 π¬ 1 π 0Yeah, probably be hard to move. Any options are good.
17.10.2025 03:53 β π 0 π 0 π¬ 0 π 0So lucky that Santander canβt see the field again this year. Guy is an absolute liability.
17.10.2025 03:52 β π 0 π 0 π¬ 0 π 0As much as Iβd love to be in Toronto this weekend, going to roll the dice on turning these bad boys into World Series duckets instead.
17.10.2025 03:49 β π 1 π 0 π¬ 2 π 0Stacey would be proud of this singer.
17.02.2025 18:17 β π 0 π 0 π¬ 1 π 0Both Conner/orβs
16.02.2025 02:37 β π 1 π 0 π¬ 0 π 0Really need Brady to start a beef with Kendrick.
10.02.2025 02:31 β π 1 π 0 π¬ 0 π 0Found him.
06.02.2025 22:35 β π 1 π 0 π¬ 0 π 0Lmao. No, there is nothing to do compared to any other NHL city.
05.02.2025 21:14 β π 1 π 0 π¬ 1 π 0It wasnβt. Complete joke.
27.01.2025 00:57 β π 1 π 0 π¬ 0 π 0Blue Jays better find a reliever. Lower backs donβt get better as the season goes on.
29.07.2023 02:09 β π 2 π 0 π¬ 0 π 0Damn. Howβd he get an invite? @thedevil.bsky.social
27.07.2023 12:02 β π 2 π 0 π¬ 0 π 0You can pretty much condense the last decade of tech into these two posts
25.07.2023 20:12 β π 3393 π 1103 π¬ 24 π 15Repost with a banger pic of you
26.07.2023 03:43 β π 1 π 0 π¬ 0 π 0lol yep. Twixtter can suck it a lot harder though π€£
25.07.2023 02:10 β π 1 π 0 π¬ 1 π 0Iβve now spent more time on here than Threads, and I joined 5 min ago.
25.07.2023 01:49 β π 13 π 0 π¬ 3 π 0