She looks very astute.
30.06.2025 12:03 β π 2 π 0 π¬ 0 π 0@itzlifelol.bsky.social
17M music enthusiast and general nerd
She looks very astute.
30.06.2025 12:03 β π 2 π 0 π¬ 0 π 0So first of all, that βreadyβ symbol has to do with the hybrid system. Something to do with the regenerative braking, I believe.
I definitely understand where you are coming from on the CVT though. I wouldnβt have an issue with hybrids if more of them had conventional transmissions.
Someone might stop for a Ford Taurus with lights that look this legitimate.
Whoever thought putting these on a Maxima was a good idea knows very little about cars. They likely figured that just about any large black or white sedan would do.
So $10,000 minimum for a DRIVERS SIDE airbag. This isnβt 1994.
29.06.2025 01:56 β π 0 π 0 π¬ 0 π 0Should be daily, but then it would no longer be a holiday.
29.06.2025 01:54 β π 2 π 0 π¬ 0 π 0They theoretically reside in a gated neighborhood!
29.06.2025 01:53 β π 0 π 0 π¬ 0 π 0tfw when you plug your phone in and it doesnβt immediately turn on:
29.06.2025 01:52 β π 1 π 0 π¬ 0 π 0He looks irritated, but patient.
29.06.2025 01:52 β π 1 π 0 π¬ 0 π 0Thoughts on their parking?
29.06.2025 01:51 β π 1 π 0 π¬ 0 π 0ts was an entire journey for bro ππ
Most likely one of the cutest and most satisfying feats of nature I have ever seen.
Of course itβs hot. Itβs Arizonaβ¦
All joking aside, glad to see it went well!
This literally looks like two parents looking at their child.
29.06.2025 01:35 β π 17 π 0 π¬ 0 π 0Dog: βIβm tired, boss.β
Meanwhile the chick: βAyo itβs a fantastic day outside. Buford! Weβve got aβ¦ Buford?β
I heard the windows xp shutdown sound effect.
29.06.2025 01:31 β π 2 π 0 π¬ 0 π 0If on the second try you donβt succeed, delete account and uninstall app.
29.06.2025 01:27 β π 2 π 0 π¬ 1 π 0[insert some random joke here]
cute
I say yes.
My bank account and furniture say no.
Iβm still letting them in.
beautiful photography!
29.06.2025 01:20 β π 1 π 0 π¬ 1 π 0no words
29.06.2025 01:20 β π 1 π 0 π¬ 0 π 0yes.
29.06.2025 01:13 β π 1 π 0 π¬ 0 π 0