Rodya
#limbus_company
#limbuscompany
@smorbies.bsky.social
she/they | i like various forms of media. i am figuring some stuff out, pfp by @kissedsuns.bsky.social | #pjmsky ? #pjmtwt
Rodya
#limbus_company
#limbuscompany
hell. yes. project moon feed
28.10.2024 06:56 β π 9 π 0 π¬ 0 π 0anyone else blueskying it rn
26.10.2024 22:10 β π 3 π 0 π¬ 2 π 0heather mason (again)
i like to think that adult heather would become a therapist or a psychologist after going though the events in silent hill
#silenthill3 #heathermason #sh #silenthill
Izutsumi
19.10.2024 03:36 β π 5 π 3 π¬ 0 π 0fair compromise
19.10.2024 11:41 β π 1 π 0 π¬ 0 π 0hello oomf
19.10.2024 11:41 β π 1 π 0 π¬ 0 π 0LIMBUS COMPANYYYYYYY
19.10.2024 11:33 β π 2 π 0 π¬ 1 π 0do i go to my place of work or do i limbus company
19.10.2024 11:32 β π 3 π 0 π¬ 2 π 0my shortcoming is not having any art finished by me so I can get as much bangers on here rather than twt.... heres this one big bird gif I got saved though
18.10.2024 00:45 β π 21 π 3 π¬ 1 π 0gregor getting the second sickly old man identity
17.10.2024 23:12 β π 2 π 0 π¬ 0 π 0Outis
17.10.2024 23:02 β π 16 π 1 π¬ 1 π 0I fw Don Quixote heavy-ish
#limbuscompany
hi guys
17.10.2024 21:52 β π 2 π 0 π¬ 0 π 0one of these days i'll end you
30.08.2024 23:56 β π 1 π 0 π¬ 0 π 0YOU CAN SEE QUOTES NOW WAIT A SECOND
30.08.2024 23:46 β π 4 π 0 π¬ 1 π 0There's an opportunity here.
30.08.2024 23:44 β π 1 π 0 π¬ 0 π 0this truly was our Blue Sky
30.08.2024 23:42 β π 3 π 0 π¬ 0 π 0no! and you can't view quotes either!
07.02.2024 14:48 β π 0 π 0 π¬ 0 π 0actually nvm im not tired yet
07.02.2024 13:14 β π 0 π 0 π¬ 0 π 0im off to skin infant babies (sleep for 12 hours) goodnight everyone
07.02.2024 13:12 β π 0 π 0 π¬ 1 π 0dawg this website sucks ?
07.02.2024 12:37 β π 2 π 0 π¬ 2 π 0YOU CANT SEE QUOTES IN THIS ???
07.02.2024 12:37 β π 0 π 0 π¬ 1 π 1where did everyone come from
07.02.2024 12:36 β π 0 π 0 π¬ 0 π 0sudden spike of activity on bluesky (two posts)
28.12.2023 11:25 β π 1 π 0 π¬ 0 π 0horse react
28.12.2023 11:24 β π 0 π 0 π¬ 0 π 0