@ammyzitta.bsky.social
Creator by @redcanids.gg Caster de League of Legends pelo @revelahcasters | Content Creator
Te amo vida ππ
08.10.2024 15:41 β π 1 π 0 π¬ 0 π 0Como eu amo a @redcanids.gg ππ
08.10.2024 15:41 β π 13 π 0 π¬ 1 π 0A SUNY Γ PERFEITA DEMAIS, ENCOMENDEM COM ELAAAAAAA
01.10.2024 22:14 β π 5 π 1 π¬ 2 π 0OBRIGADA π₯Ήβ€οΈ
29.09.2024 15:02 β π 1 π 0 π¬ 0 π 0πβ€οΈπΊ
29.09.2024 15:02 β π 0 π 0 π¬ 0 π 0Aaaaaaaaa muito obrigada πβ€οΈ
29.09.2024 15:01 β π 0 π 0 π¬ 0 π 0
Oieerrrr
VocΓͺ Γ© influenciador de Valorant e tem interesse em transmitir campeonatos? Fala comigo aqui β¨
Para quem nΓ£o me conhece, meu nome Γ© Rita e sou influencer specialist na Riot Games. Qualquer coisa que vocΓͺ, creator/influencer, precisar das IPs Valorant e 2Xko, podem falar comigo
Obrigada π₯Ήβ€οΈ
29.09.2024 02:00 β π 0 π 0 π¬ 0 π 0Obrigadaaaa π₯Ήβ€οΈ
27.09.2024 19:45 β π 1 π 0 π¬ 0 π 0Obrigadaaaaa πΊβ€οΈπ₯Ή
27.09.2024 19:45 β π 0 π 0 π¬ 0 π 0OBRIGADA ππ«Άβ€οΈ
27.09.2024 19:45 β π 0 π 0 π¬ 0 π 0AAAAAAAAAA πβ€οΈ
27.09.2024 19:45 β π 0 π 0 π¬ 0 π 0OBRIGADA MEDU Γ UMA HONRA
27.09.2024 19:44 β π 1 π 0 π¬ 0 π 0Obrigada π«Άπ₯Ήβ€οΈ
27.09.2024 19:44 β π 1 π 0 π¬ 0 π 0Obrigada xarΓ‘ π₯Ήβ€οΈπΊ
27.09.2024 17:37 β π 1 π 0 π¬ 0 π 0Obrigadaaaaaaaa
27.09.2024 17:37 β π 1 π 0 π¬ 0 π 0Aaaaaaaaaaa obrigadaaaa sove πβ€οΈ
27.09.2024 17:37 β π 1 π 0 π¬ 0 π 0KKKKKKKK vΓ΄ te da orgulho chefe π«‘
27.09.2024 17:37 β π 2 π 0 π¬ 0 π 0Obrigada Ismaaaaa π«Άβ€οΈ
27.09.2024 17:36 β π 1 π 0 π¬ 0 π 0Obg π₯Ήβ€οΈπ₯Ήβ€οΈ
27.09.2024 17:36 β π 0 π 0 π¬ 0 π 0Obrigada π«Άπ«Ά
27.09.2024 17:36 β π 1 π 0 π¬ 0 π 0Kkkkkkkkkkkk obrigadaaaa π₯Ήβ€οΈ
27.09.2024 17:36 β π 1 π 0 π¬ 0 π 0Muito obrigada π₯Ήβ€οΈ
27.09.2024 17:36 β π 1 π 0 π¬ 0 π 0Obrigada π₯Ήβ€οΈ
27.09.2024 17:35 β π 1 π 0 π¬ 0 π 0Obrigadaaaaaaa β€οΈ
27.09.2024 17:35 β π 1 π 0 π¬ 0 π 0Obrigada π₯Ήβ€οΈ
27.09.2024 17:35 β π 1 π 0 π¬ 0 π 0Obrigada filhos! πβ€οΈ
27.09.2024 17:35 β π 0 π 0 π¬ 0 π 0Hiiii π₯Ή
27.09.2024 17:33 β π 0 π 0 π¬ 0 π 0Obrigada πβ€οΈ
27.09.2024 17:33 β π 1 π 0 π¬ 0 π 0Obrigadaaaa π«Ά
27.09.2024 17:33 β π 0 π 0 π¬ 0 π 0
