TNT 5G Panalo Phone, Now the Most Affordable 5G Phone in the Philippines for ONLY P3,990! β’ Digital Reg | Since 2004 β’ Tech Review
TNT unveiled the new TNT 5G Panalo Phone, now the most affordable 5G smartphone in the Philippines for only P3,990. Available at accredited retailers
TNT unveiled the new TNT 5G Panalo Phone, now the most affordable 5G smartphone in the Philippines for only P3,990. They also launched TNT 5G Max - a boosted network experience that delivers faster speeds and more reliable connectivity for subscribers.
Read the story: digitalreg.net/news/technol...
30.11.2024 05:44 β π 0 π 0 π¬ 0 π 0
New Game-Changer Sedan BYD Seal 5 DM-i Launched β’ Digital Reg | Since 2004 β’ Tech Review
BYD Cars Philippines, in collaboration with ACMobility, proudly introduces the BYD Seal 5 DM-i, a groundbreaking sedan tailored specifically for practical and
The BYD Seal 5 DM-i is a groundbreaking sedan tailored specifically for practical and progressive first-time car buyers. The new electric vehicle offers a premium driving experience at an accessible price point, making electric mobility more accessible to Filipinos.
digitalreg.net/cars-motorcy...
28.11.2024 08:08 β π 1 π 0 π¬ 0 π 0
Thinking twice about getting an iPad Mini 7. I have no use for it except for watching videos. Might settle for an Apple Watch instead.
18.11.2024 05:33 β π 0 π 0 π¬ 0 π 0
Using the AI Transcription and Translation features of the HONOR Magic V3. I tried recording a few sentences and set the translation to German. It transcribed every word Iβve said! Then I selected the words and had the Magic V3 read them aloud! So cool! #HONORMagicV3
17.11.2024 06:41 β π 1 π 0 π¬ 0 π 0
ang sarap ng feeling! i feel so free being here! itβs not the same anymore in the other platform.
17.11.2024 04:27 β π 1 π 0 π¬ 0 π 0
TikTok - Make Your Day
Unboxed the HONOR Magic V3. Watch it here: vt.tiktok.com/ZSj5xCENc/
#HONORMagicV3 #FoldablePhone #TechUnboxing
17.11.2024 04:20 β π 0 π 0 π¬ 0 π 0
Itβs like opening my Twitter account back in 2007.
17.11.2024 04:13 β π 2 π 0 π¬ 1 π 0