In fact, the reporter - again, this is true - said they'd have to independently verify that Jim Crow happened because it sounded like I was pushing a specific agenda.
18.02.2025 17:33 β π 4142 π 360 π¬ 138 π 44@voiceofcharles.bsky.social
Actor and voiceover actor living in Chicago. www.voiceofcharles.com
In fact, the reporter - again, this is true - said they'd have to independently verify that Jim Crow happened because it sounded like I was pushing a specific agenda.
18.02.2025 17:33 β π 4142 π 360 π¬ 138 π 44True story: a few years ago, I was being interviewed by a reporter for the New York Times. I mentioned the history of eviction statutes and how they tied into Jim Crow.
The reporter asked "what's Jim Crow?"
When I explained, the reporter didn't believe me and said the US wouldn't do that.
"Hibachi Baby Terror" is a killer band name...
21.02.2025 08:43 β π 0 π 0 π¬ 0 π 0I adore this film.
29.01.2025 04:51 β π 1 π 0 π¬ 1 π 0Seeing as we appear to be on the darkest time line, if anyone knows Donna Noble please tell her to TURN LEFT. Thank you.
29.01.2025 04:50 β π 3 π 0 π¬ 0 π 0The last five days have been the longest year of my life...
25.01.2025 04:39 β π 0 π 0 π¬ 0 π 0Hey hey! Was just thinking about you the other day! π
17.01.2025 04:31 β π 0 π 0 π¬ 1 π 0What's going on here?! Am I taking crazy pills?!!
17.01.2025 04:14 β π 0 π 0 π¬ 0 π 0You are a gem. β€οΈ
17.01.2025 04:13 β π 0 π 0 π¬ 0 π 0Thank you, sir. I did need this today. π
17.01.2025 04:12 β π 0 π 0 π¬ 0 π 0Awesome! Thank you. Btw, who are you? π
17.01.2025 04:11 β π 0 π 0 π¬ 1 π 0Ah - one-ah - and-ah- two-ah - and-ah - three-ah...
*shudders*
...the horror...
I've heard somewhere that Connery's character in 'The Rock' was supposed to be a retired James Bond.
13.01.2025 21:42 β π 0 π 0 π¬ 1 π 0@marcelias.bsky.social It may be petty, but I was fantasizing about a protest as Trump was on his way to the inauguration with the streets *filled* with people along the route standing with their backs to him. All. The. Way. There.
05.12.2024 19:29 β π 6 π 1 π¬ 0 π 0